6y^2+61y+10=0

Solution for 6y^2+61y+10=0 equation:

6y^2+61y+10=0

a = 6; b = 61; c = +10;
Δ = b2-4ac
Δ = 612-4·6·10
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-59}{2*6}=\frac{-120}{12}
=-10
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+59}{2*6}=\frac{-2}{12}
=-1/6
$